A) \[VOS{{O}_{4}}\]
B) \[N{{a}_{3}}V{{O}_{4}}\]
C) \[[V{{({{H}_{2}}O)}_{6}}]S{{O}_{4}}.{{H}_{2}}O\]
D) \[MnO_{4}^{2-}\]
Correct Answer: A
Solution :
We know that Q = it \[Cd(s)+2Ni{{(OH)}_{3}}(s)\xrightarrow{{}}CdO(s)\] For depositing 1 mol \[+2Ni{{(OH)}_{2}}(s)+{{H}_{2}}O(l)\] charge \[Pb(s)+Pb{{O}_{2}}(s)+2{{H}_{2}}S{{O}_{4}}(aq)\xrightarrow{{}}\] For depositing 1 mill mole of \[Al\] charge \[=3\times 96500\times {{10}^{-3}}C\] \[t=\frac{Q}{i}=\frac{3\times 96.5}{9.65}=30s\]
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