A) 1.5 A
B) 3.0 A
C) 15 A
D) 300 A
Correct Answer: A
Solution :
Key Idea: Find the equivalent circuit of consisting of net emf, net resistance. In each row all the 5000 electro-plaques are connected in series and all the 100 rows are connected in parallel. Hence, equivalent emf is \[5000\times 0.15=750V\] Equivalent resistance \[=0.25\times 5000\] \[=1250\Omega \] Now, the circuit of eel is redrawn as, Voltage across resistors connected in parallel is same, also equivalent resistance is \[\frac{1250}{100}=12.5\Omega \] From Ohms law, \[V=IR\] \[\therefore \] \[I=\frac{V}{R}=\frac{750}{500+12.5}=1.46A\] \[\therefore \] \[I\approx 1.5A\]You need to login to perform this action.
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