A) OR
B) NAND
C) AND
D) NOR
Correct Answer: C
Solution :
Key Idea: First two similar gates are NOT gates and the third one is NOR gate. The simple diagram can be shown as: The output of gate -\[1=\overline{A}\] The output of gate-2 = B The output of gate-3 \[y=\overline{\overline{A}+\overline{B}}\] Use Demorgans theorem \[\overline{\overline{A}+\overline{B}}=\overline{\overline{A}}.\overline{\overline{B}}\] Hence, \[y=\overline{\overline{A}}.\overline{\overline{B}}\] \[y=A.B\] This is the Boolean expression of AND gate. Note: We can define NOR gate as: The OR gate followed by NOT gate as shown.You need to login to perform this action.
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