A) \[HCl{{O}_{4}}\]
B) \[+7\]
C) \[HCl{{O}_{3}}+5\]
D) \[Cr\]
Correct Answer: A
Solution :
Octahedral complexes of type \[10.0\]\[6.1\] \[7.1\], \[{{I}_{2}}(g)\rightleftharpoons 2I(g),\Delta H_{r}^{o}(298K)=+150kJ\] \[I\] \[{{I}_{2}}\]and \[{{N}_{2}}{{O}_{5}}(g)\xrightarrow{{}}2N{{O}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\] show optical isomerism due to asymmetric molecules. Octahedral complexes of type \[2.3\times {{10}^{-2}}{{s}^{-1}}\] and \[[{{N}_{2}}{{O}_{5}}]\] do not show optical isomerism due to presence of plane of symmetry. Hence \[{{[{{N}_{2}}{{O}_{5}}]}_{0}}\]will not show optical isomerism.
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