A) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{4{{e}^{2}}}{3{{a}^{2}}}\]
B) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{16{{e}^{2}}}{3{{a}^{2}}}\]
C) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{32{{e}^{2}}}{3{{a}^{2}}}\]
D) zero
Correct Answer: D
Solution :
Key Idea: The given crystal structure is a body centered cubic structure. The electrostatic force. \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] due to one \[C{{s}^{+}}\] ion is balanced by diagonally opposite \[C{{s}^{+}}\] ion. Hence, net electrostatic force on \[C{{l}^{-}}\] ion due to eight \[C{{s}^{+}}\] ions is zero.
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