A) \[+3\]
B) \[+5\]
C) \[4-1,4-2,\]
D) PCC (pyridine chloro chromate)
Correct Answer: D
Solution :
Pyridinium chlorochromate (PCC) \[KMn{{O}_{4}}\] is a very good oxidising agent for converting \[MnS{{O}_{4}}\] alcohol to aldehydes and \[\begin{matrix} 2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}{{K}_{2}}S{{O}_{4}} \\ +2MnS{{O}_{4}}+3{{H}_{2}}O+5[O] \\ [{{H}_{2}}{{O}_{2}}+O\xrightarrow{{}}{{H}_{2}}O+{{O}_{2}}]\times 5 \\ \begin{align} & \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\ & \underset{Pink}{\mathop{2KMn{{O}_{4}}+5{{H}_{2}}{{O}_{2}}+3{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{}}}\, \\ & {{K}_{2}}S{{O}_{4}}+\underset{colourless}{\mathop{2MnS{{O}_{4}}}}\,+8{{H}_{2}}O+5{{O}_{2}} \\ \end{align} \\ \end{matrix}\] alcohols to Icetone. It prevents further oxidation of aldehydes to carboxylic acid. \[KMn{{O}_{4}}\] [PCC is prepared by mixing pyridine\[{{H}_{2}}{{O}_{2}}\] and \[\therefore \]. \[KMn{{O}_{4}}\] \[\frac{5}{2}\]
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