A) \[4-4\]
B) \[{{N}_{2}}O,NO,{{N}_{2}}{{O}_{3}},N{{O}_{2}}\]
C) \[{{N}_{2}}{{O}_{5}}\]
D) \[4-1\]
Correct Answer: D
Solution :
The order of heat of vaporization or boiling point of the following hydrides of VA group elements is \[{{H}_{2}}{{O}_{2}}\] Boiling point increase with increase in molecular mass hence, boiling point of \[(N_{3}^{-})\] should be maximum and that of \[(N_{3}^{-})\] should be minimum. But \[Be{{(OH)}_{2}}\] has highest boiling point because of H-bond present in \[Be{{(OH)}_{2}}\].
You need to login to perform this action.
You will be redirected in
3 sec
