A) 5.0
B) 6.0
C) 7.0
D) 9.0
Correct Answer: C
Solution :
\[p{{K}_{a}}=-\log {{K}_{a}}\] and \[p{{K}_{b}}=-\log {{K}_{b}}\] \[pH=-\frac{1}{2}[\log {{K}_{a}}+\log {{K}_{w}}-\log {{K}_{b}}]\] \[=-\frac{1}{2}[-5+\log {{10}^{-14}}-(-5)]\] \[=-\frac{1}{2}[-5-14+5]\] \[=7\] Thus, the end point or equivalence point is obtained at pH = 7 in neutral medium.You need to login to perform this action.
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