A) 1.1 mA
B) 1.01mA
C) 0.01 mA
D) 10 mA
Correct Answer: B
Solution :
Key Idea: Current gain is defined as ratio of collector current to base current. \[3/2{{v}_{0}}\] \[\ge \sqrt{\frac{10}{7}gh}\] Also, \[\ge \sqrt{2gh}\] \[2gh\] \[\frac{10}{7}gh\] \[{{r}_{A}}\] Given, \[{{r}_{B}}\] \[({{r}_{B}}>{{r}_{A}})\] \[{{Q}_{A}}\] \[{{Q}_{B}}\] \[(\left| {{Q}_{B}} \right|>\left| {{Q}_{A}} \right|).\] Note: In common-emitter amplifier, the output voltage signal is 180° out of phase with the input voltage signal.
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