A) \[\therefore \]
B) \[100=\frac{1}{\Delta {{i}_{E}}-1}\]
C) \[\Delta {{i}_{E}}=1=\frac{1}{100}=0.01\]
D) \[\Delta {{i}_{E}}=1+0.01=1.01mA.\]
Correct Answer: A
Solution :
From Bohrs model of atom, electrons can revolve only in those orbits in which their angular momentum is an integral multiple of \[Fdx={{K}_{f}}-\frac{1}{2}mv_{i}^{2}\] where h is Plancks universal constant. From Bohrs postulate \[F.dx={{K}_{f}}-\frac{1}{2}\times 10\times {{(10)}^{2}}\] \[\Rightarrow \] \[F.dx={{K}_{f}}-500\] where n is integer (= 1, 2, 3,.......) and is called principal quantum number. Note: The discrete orbits in which electrons can revolve are known as stable orbits.
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