A) \[{{[Ni{{(CN)}_{4}}]}^{2-}}\]
B) \[{{[NiC{{l}_{4}}]}^{2-}}\]
C) \[{{[CoC{{l}_{4}}]}^{2-}}\]
D) \[{{[Co{{F}_{6}}]}^{2-}}\]
Correct Answer: A
Solution :
The decreasing order of strength of ligands is \[\underbrace{CO>C{{N}^{-}}>NO_{2}^{-}>N{{H}_{3}}>}_{\begin{smallmatrix} Strong\,field\,ligand \\ cause\,pairitng\,of\,electrons \end{smallmatrix}}\] \[\underbrace{{{H}_{2}}O>{{F}^{-}}>C{{l}^{-}}>B{{r}^{-}}>{{I}^{-}}}_{\begin{smallmatrix} Weak\,field\,ligand\,does \\ not\,cause\,parining \end{smallmatrix}}\] \[N{{i}^{2+}}\] in presence of \[C{{N}^{-}}\] \[n=0\] (diamagnetic) \[ds{{p}^{2}}\] hybridisation, low spin complex. \[N{{i}^{2+}}\] in presence of weak ligand \[C{{l}^{-}}\] \[n=2\], paramagnetic \[s{{p}^{3}}\], hybridisation, high spin complex. \[C{{o}^{2+}}\] in presence of weak ligand \[C{{l}^{-}}\] \[n=3\], paramagnetic, \[s{{p}^{3}}\] hybridisation \[C{{o}^{2+}}\] in presence of weak ligand \[{{F}^{-}}\] \[n=5\], paramagnetic, \[s{{p}^{3}}{{d}^{2}}\] hybridisationYou need to login to perform this action.
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