A) \[C{{H}_{3}}C{{H}_{2}}CH(OC{{H}_{3}})C{{H}_{3}}\]
B) \[C{{H}_{3}}CH=CHC{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OC{{H}_{3}}\]
Correct Answer: B
Solution :
According to Saytzeff rule during dehydrohalogenation of an alkyl halide H-atom is removed from that C-atom which has lesser number of hydrogen atoms (f. e., to form) more alkylated alkene. \[C{{H}_{3}}C{{H}_{2}}CH(F)C{{H}_{3}}\xrightarrow[C{{H}_{3}}OH]{C{{H}_{3}}ONa\,(base)}\]You need to login to perform this action.
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