A) \[PE=2E\]
B) \[E=-136eV\]
C) \[\therefore \]
D) \[PE=-2\times 13.6\]
Correct Answer: B
Solution :
From ohms law \[=\frac{1}{2}\frac{KZ{{e}^{2}}}{r}-\frac{KZ{{e}^{2}}}{r}\] where V is voltage, R is resistance and I is current. \[=\frac{KZ{{e}^{2}}}{2r}\] \[PE=2E\] \[E=-136eV\] \[\therefore \] Alternative: From definition of time constant t =RC, where R is resistance C is capacitance. \[PE=-2\times 13.6\] \[=-27.2eV\] \[f=(2.48\times {{10}^{15}}){{(Z-1)}^{2}}Hz\]
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