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AIIMS AIIMS Solved Paper-2005

  • question_answer
    A particle having charge q and mass m is projected with velocity \[=-27.2eV\]in uniform electric field \[f=(2.48\times {{10}^{15}}){{(Z-1)}^{2}}Hz\]. Change in momentum \[\Rightarrow \] during any time interval t is given by:

    A) \[f\propto {{Z}^{2}}\]                                    

    B) \[+\sigma \]                      

    C)       \[-\sigma \]                       

    D)       zero

    Correct Answer: B

    Solution :

                                    The product of force and time interval is called impulse. Also from Newtons second law, we have \[\Rightarrow \] \[f\propto {{Z}^{2}}\] The force on charge q due to electric field is \[+\sigma \]. \[-\sigma \]  Impulse  \[E=E+E=2E\]


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