A) decreases continuously
B) decreases initially and increases again
C) remains unaltered
D) increases continuously
Correct Answer: B
Solution :
From law of conservation of angular momentum if no external torque is acting upon a body rotating about an axis, then the angular momentum of the body remains constant that is \[=\frac{1}{2}m{{v}^{2}}=\frac{KZ{{e}^{2}}}{2r}\] Hence, if \[I\] decreases, \[\omega \] increases and vice- versa. When liquid is dropped, mass increases hence I increases \[=\frac{KZe}{r}\]. So, \[\therefore \]decreases, but as soon as the liquid starts falling \[=\text{ }potential\text{ }\times \text{ }charge\] increases again.You need to login to perform this action.
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