A) \[0.2\,\,kg\,m{{s}^{-1}}\]
B) \[-0.2\,kg\,m{{s}^{-1}}\]
C) \[0.1\,\,kg\,m{{s}^{-1}}\]
D) \[-0.4\,kg\,m{{s}^{-1}}\]
Correct Answer: A
Solution :
If a constant force F is applied on a body for a short interval of time At, then impulse of this force is \[{{\sin }^{2}}t\omega t\]. From Newtons second law \[\sin \,\,\omega t+\sin \,\,2\,\,\omega t\] \[\sin \,\,\omega t-\sin \,\,2\,\,\omega t\] \[\sim 1.2\times {{10}^{12}}{{m}^{-3}}\] \[\sim {{10}^{6}}{{m}^{-3}}\] Impulse, \[\sim {{10}^{14}}{{m}^{-3}}\] Given, \[\sim {{10}^{22}}{{m}^{-3}}\] \[{{\sin }^{-1}}({{n}_{2}}/{{n}_{1}})\] \[{{\sin }^{-1}}\sqrt{n_{1}^{2}-n_{2}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
