A) \[T{{i}^{+}},T{{i}^{3+}}\]
B) \[C{{u}^{+}},C{{u}^{2+}}\]
C) \[C{{r}^{2+}},C{{r}^{3+}}\]
D) \[{{V}^{2+}},V{{O}^{2+}}\]
Correct Answer: A
Solution :
As we move down in 13, 14 and 15 groups the inertness of \[{{s}^{2}}\] electrons of valence shell increases and therefore, metals in the lower portion of the group show lower oxidation state e.g., lead show \[+2\] in spite of \[+4\]. Similarly \[+3\] oxidation State of bismuth is more stable than \[+5\] oxidation state. Thus, due to inert pair effect, titanium shows \[+1\]oxidation state rather than \[+3\].
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