A) \[7.50\times {{10}^{-5}}\]
B) \[2.50\times {{10}^{-5}}\]
C) \[2.50\times {{10}^{-4}}\]
D) \[1.72\times {{10}^{-4}}\]
Correct Answer: D
Solution :
\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] \[\Delta n\]= change in gaseous moles. For the reaction \[2NOCl(g)\rightleftharpoons 2NO(g)+C{{l}_{2}}(g)\] \[{{K}_{c}}=3\times {{10}^{-6}}\,L\,mo{{l}^{-1}},R=0.0821\,L\,atm/Kmol\] \[\Delta n=3-2=1\] \[T=427+273=700K\] \[{{K}_{P}}=3\times {{10}^{-6}}\times {{(0.0821\times 700)}^{1}}\] \[=1.72\times {{10}^{-4}}\]You need to login to perform this action.
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