A) \[4.74\]
B) \[2.26\]
C) \[9.26\]
D) \[5.00\]
Correct Answer: C
Solution :
Handerson- Hasselbalch equation \[pOH=p{{K}_{b}}+\log \frac{[salt]}{[base]}\] At half stage of titration [salt] = [base] as \[pOH=p{{K}_{b}}=4.74\] \[pH=14-pOH=14-4.74=9.26\]You need to login to perform this action.
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