A) \[\frac{1}{48}M{{L}^{2}}\]
B) \[\frac{1}{12}M{{L}^{2}}\]
C) \[\frac{1}{24}M{{L}^{2}}\]
D) \[\frac{M{{L}^{2}}}{8\sqrt{3}}\]
Correct Answer: B
Solution :
Since, rod is bent at the middle, so each part of it will have same length \[\left( \frac{L}{2} \right)\] and mass \[\left( \frac{M}{2} \right)\] as shown. Moment of inertia of each part through its one end \[=\frac{1}{3}\left( \frac{M}{2} \right){{\left( \frac{L}{2} \right)}^{2}}\] Hence, net moment of inertia through its middle point O is \[I=\frac{1}{3}\left( \frac{M}{2} \right){{\left( \frac{L}{2} \right)}^{2}}+\frac{1}{3}\left( \frac{M}{2} \right){{\left( \frac{L}{2} \right)}^{2}}\] \[=\frac{1}{3}\left[ \frac{M{{L}^{2}}}{8}+\frac{M{{L}^{2}}}{8} \right]=\frac{M{{L}^{2}}}{12}\]You need to login to perform this action.
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