A) 5
B) 8
C) 10
D) 20
Correct Answer: A
Solution :
Lens formula is given by \[\frac{1}{f}=\frac{1}{\upsilon }-\frac{1}{u}\] ?..(i) where f is focal length of lens, v is image distance and u is object distance. Given, f= 10 cm (as lens is converging) \[u=-8\text{ }cm\] (as object is placed on left side of the lens) Substituting these values in Eq. (i), we get \[\frac{1}{10}=\frac{1}{v}-\frac{1}{-8}\] \[\Rightarrow \] \[\frac{1}{v}=\frac{1}{10}-\frac{1}{8}\] \[\Rightarrow \] \[\frac{1}{v}=\frac{8-10}{80}\] \[v=\frac{80}{-2}=-40cm\] Hence, magnification produced by the lens \[m=\frac{v}{u}=\frac{-40}{-8}=5\]You need to login to perform this action.
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