A) \[2\]
B) \[3\]
C) \[4\]
D) \[6\]
Correct Answer: C
Solution :
In \[Ag{{[{{(CN)}_{2}}]}^{2-}},\,\,C{{N}^{-}}\] has \[\pi \] bonds \[C\equiv N\] so two \[\pi \] -bonds are present in one CN so, the number of \[\pi \] bonds are \[2\times 2=4\].You need to login to perform this action.
You will be redirected in
3 sec