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AIIMS AIIMS Solved Paper-2007

  • question_answer
    A common emitter amplifier has a voltage gain of 50, an input impedance of 100\[({{T}_{n}})\] and an output impedance of 200\[{{T}_{i}}-{{T}_{n}}={{T}_{n}}-T\]. The power gain of the amplifier is  

    A)  500  

    B)                                        1000                     

    C)        1250                     

    D)        100

    Correct Answer: C

    Solution :

    AC power gain \[\beta \] \[k\Omega \] \[\mu F\] where \[{{A}_{V}}\] is voltage gain and \[(h=6.6\times {{10}^{-34}}J-s1cal=4.2J)\] is AC current gain. Also, \[\overset{0}{\mathop{A}}\,\] Given, \[R=\alpha \] Hence, \[\alpha \] \[\mu k\]               \[\mu k\] Now, AC power gain \[\mu k\]                                                 \[\mu k\]


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