A) \[(h=6.6\times {{10}^{-34}}J-s1cal=4.2J)\]
B) \[\overset{0}{\mathop{A}}\,\]
C) \[R=\alpha \]
D) \[\alpha \]
Correct Answer: C
Solution :
Let displacement equation of particle executing SHM is \[\frac{qv{{R}^{2}}}{2}\] As particle travels half of the amplitude from the equilibrium position, so \[qvR\] Therefore, \[{{L}_{A}}\] or \[{{L}_{B}}\] or \[{{L}_{A}}>{{L}_{B}}\] or \[{{L}_{A}}={{L}_{B}}\] or \[{{L}_{A}}\] \[{{L}_{B}}\] or \[{{L}_{A}}<{{L}_{B}}\] Hence, the particle travels half of the amplitude from the equilibrium in \[\Omega \] s.You need to login to perform this action.
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