A) 40m/s
B) 20 m/s
C) 10 m/s
D) 10\[qv{{R}^{2}}\] m/s
Correct Answer: A
Solution :
According to conservation of energy: \[v_{f}^{2}=v_{i}^{2}+\frac{2G{{m}_{e}}}{{{R}_{e}}}\left( 1+\frac{1}{10} \right)\] or \[v_{f}^{2}=v_{i}^{2}+\frac{2G{{m}_{e}}}{{{R}_{e}}}\left( 1-\frac{1}{10} \right)\] or \[v_{f}^{2}=v_{i}^{2}+\frac{2Gm}{{{R}_{e}}}\left( 1-\frac{1}{10} \right)\] or \[\mathbf{\vec{v}}\]You need to login to perform this action.
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