A) \[CO_{3}^{2-}\]
B) \[BC{{l}_{3}}\]
C) \[N{{(Si{{H}_{3}})}_{3}}\]
D) all of these
Correct Answer: D
Solution :
C in \[CO_{3}^{2-}\] and B in \[BC{{l}_{3}}\] are \[s{{p}^{2}}\] hybridised thus acquire planar geometry. Although N in \[N{{(Si{{H}_{3}})}_{3}}\] is \[s{{p}^{3}}\] hybridised but the steric hinderence caused by three bulky groups make it planar for higher stability.
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