A) \[{{I}_{2}}{{O}_{4}}\]
B) \[{{I}_{2}}{{O}_{5}}\]
C) \[{{I}_{2}}{{O}_{7}}\]
D) \[{{I}_{2}}{{O}_{9}}\]
Correct Answer: A
Solution :
In general, higher the oxidation state, more is the covalent character of the oxide. \[{{I}_{2}}{{O}_{7}}\] and \[{{I}_{2}}{{O}_{9}}\] do not exist. \[{{I}_{2}}{{O}_{4}}\] is ionic in nature. It is infact iodyl iodate \[{{[IO]}^{+}}\,\,{{[I{{O}_{3}}]}^{-}}\]. The only covalent oxide of iodine is \[{{I}_{2}}{{O}_{5}}\].
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