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AIIMS AIIMS Solved Paper-2007

  • question_answer
    One mole of methanol when burnt in \[{{O}_{2}}\], gives out  \[723\text{ }kJ\text{ }mo{{l}^{-1}}\]heat. If one mole of \[{{O}_{2}}\] is used, what will be the amount of heat evolved?

    A)  723 kJ                  

    B)         924 kJ  

    C)         482 kJ                  

    D)         241 kJ

    Correct Answer: C

    Solution :

    \[C{{H}_{3}}OH(l)+\frac{3}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g)+2{{H}_{2}}O(l)\] \[\Delta H=-732kJ\] By burning with \[\frac{3}{2}{{O}_{2}}(g)\]heat evolved \[=-723kJ\] \[\therefore \]By burning with 1 mole \[{{O}_{2}}(g)=\frac{-732\times 2}{3}\] \[=-482kJ\]


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