A) \[-208.1\,kJ\,\,mo{{l}^{-1}}\]
B) \[-269.9\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[-358.5\text{ }kJ\,\,mo{{l}^{-1}}\]
D) \[-508.9\text{ }kJ\,\,mo{{l}^{-1}}\]
Correct Answer: A
Solution :
The enthalpy of hydrogenation of cyclohexene (having one double bond) is \[-119.5kJ\,\,mo{{l}^{-1}}.\] Hence, theoretically enthalpy of hydrogenation of Kekules structure of benzene should be \[3\times (-119.5)\text{ }kJ\text{ }mo{{l}^{-1}}\]. Since the resonance energy of benzene is \[-150.4\text{ }kJ\text{ }mo{{l}^{-1}}\], the actual enthalpy of hydrogenation of benzene will be, \[=[3\times (-119.5)]-(-150.4)\] \[=-208.1kJmo{{l}^{-1}}.\]
You need to login to perform this action.
You will be redirected in
3 sec
