A) copper
B) iron
C) lead
D) mercury
Correct Answer: B
Solution :
Hydrogen cannot be prepared by the action of dil. \[{{H}_{2}}S{{O}_{4}}\] on copper or mercury as these two metals cannot displace hydrogen from acids. Action of dil. \[{{H}_{2}}S{{O}_{4}}\]on \[Pb\] stops after some time due to the formation of insoluble \[PbS{{O}_{4}}\]. Only iron reacts rapidly with dil. \[{{H}_{2}}S{{O}_{4}}\] to give \[{{H}_{2}}\].
You need to login to perform this action.
You will be redirected in
3 sec
