A) \[2\times {{10}^{11}}\]
B) \[4\times {{10}^{12}}\]
C) \[1\times {{10}^{2}}\]
D) \[1\times {{10}^{10}}\]
Correct Answer: D
Solution :
\[E_{cell}^{o}=\frac{2.303RT}{nF}\log {{K}_{eq}}\] \[0.295=\frac{2.303\times 8.314\times 298}{2\times 96500}\log {{K}_{eq}}\] \[\log {{K}_{eq}}=\frac{2.303\times 96500\times 0.295}{2.303\times 8.314\times 298}\] \[=10\] \[{{\text{K}}_{\text{eq}}}\text{=antilog10}\] \[=1\times {{10}^{10}}\]
You need to login to perform this action.
You will be redirected in
3 sec
