A) \[{{K}_{c}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\]
B) \[KOH\]
C) \[O-\]
D) \[KOH\]
Correct Answer: A
Solution :
According to Heisenberg \[HCl\] For particle A \[C{{H}_{3}}CHO,\] \[C{{H}_{3}}CHO,\] \[NaOH\] So, \[A\rightleftharpoons B;\,\,K=0.001\] For particle B \[M\rightleftharpoons N;\,\,K=10\] \[X\rightleftharpoons Y;\,\,K=0.005\] \[R\rightleftharpoons P;\,\,K=0.01\] So, \[{{B}_{12}}\] Eq. (i)/(ii), we get \[M{{g}^{2+}}\]You need to login to perform this action.
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