A) 0.4 m/s
B) 0.133 m/s
C) 0.1 m/s
D) 0.2 m/s
Correct Answer: C
Solution :
Terminal speed of spherical body in a viscous liquid is given by \[n=3\] where \[{{f}_{0}}=\frac{v}{2L}=\frac{315}{3}=105Hz\] = density of substance of body and \[{{v}_{T}}=\frac{2{{r}^{2}}(\rho -\sigma )g}{9\eta }\] = density of liquid. From given data \[\rho \] \[\sigma \] \[\frac{{{v}_{T}}(Ag)}{{{v}_{T}}(Gold)}=\frac{{{\rho }_{Ag}}-{{\sigma }_{l}}}{{{\rho }_{Gold}}-{{\sigma }_{l}}}\]You need to login to perform this action.
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