A) 1/2
B) 1/4
C) 1/3
D) 2/3
Correct Answer: C
Solution :
According to the figure \[{{v}_{app}}=|{{v}_{1}}|+|{{v}_{2}}|=\sqrt{\frac{2G}{r}({{m}_{1}}+{{m}_{2}})}\] \[l={{10}^{-4}}m,\,\,F=20N,\] \[A={{10}^{-6}}{{m}^{2}},L=1m\] \[\therefore \] \[Y=\frac{FL}{Al}\] \[=\frac{20\times 1}{{{10}^{-6}}\times {{10}^{-4}}}\]You need to login to perform this action.
You will be redirected in
3 sec