A) 5%
B) 7.2%
C) 12.5%
D) 11.1%
Correct Answer: D
Solution :
When T is constant, \[pV=\] constant. When volume is decreased by 10% that is volume becomes \[\frac{90}{100},\], the pressure must become 100/99. \[\therefore \] % increase in pressure \[=\frac{(100-90)\times 100}{90}\] \[=11.1%\]You need to login to perform this action.
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