A) \[F{{e}^{3+}}\]
B) \[F{{e}^{3+}}=[Ar]3{{d}^{5}},4{{s}^{0}}\]
C) \[{{[Fe{{({{H}_{2}}O)}_{6}}]}^{3+}}=[Ar]\]
D) \[S{{O}_{2}}\]
Correct Answer: C
Solution :
When nitric acid \[Ca{{({{H}_{2}}P{{O}_{4}})}_{2}}+2CaS{{O}_{4}}.\] reacts with nitric oxide \[pH=10\] gas is released which oxidises \[\therefore \] into sulphur. The reactions are as follows: \[[{{H}^{+}}]=1\times {{10}^{-pH}}=1\times {{10}^{-10}}mol/L\] \[\therefore \]
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