A) \[KOH\]
B) \[{{k}_{1}}=3{{k}_{2}}\,=1.5\,{{k}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}\]
Correct Answer: B
Solution :
\[\therefore \] Rate \[C{{H}_{3}}\] or\[=-158kcal/mol\] or \[\Delta {{H}_{comb}}({{C}_{10}}{{H}_{22}})=\Delta {{H}_{comb}}(C{{H}_{4}})+\]
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