A) \[{{t}_{1/2}}\]
B) \[5.13\times {{10}^{12}}yr\]
C) \[1.628\times {{10}^{5}}yr\]
D) \[2.94\times {{10}^{-9}}yr\]
Correct Answer: C
Solution :
Given, \[\therefore \] \[S=4.59\times {{10}^{-5}}\] \[{{M}_{2}}X,\] \[{{M}_{2}}X\rightleftharpoons \underset{2s}{\mathop{2{{M}^{+}}}}\,+\underset{s}{\mathop{{{X}^{2-}}}}\,\] \[{{K}_{sp}}={{(2s)}^{2}}.(s)\] \[{{K}_{sp}}=4{{s}^{2}}\] The number of hydroxyl ions present in \[{{K}_{sp}}=4{{(2\times 4.59\times {{10}^{-5}})}^{3}}\] \[\because \] The number of hydroxyl ions in \[{{M}_{2}}X=2\times \] In 1000 mL number of hydroxyl ions \[{{M}_{2}}{{X}_{3}}\] \[=3\text{ }\times {{10}^{-12}}\] In 100 mL number of hydroxyl ions \[-C{{H}_{3}}\] \[C{{H}_{3}}COO-Hg-OCOC{{H}_{3}}\xrightarrow{{}}\]
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