question_answer

The solubility product of a salt having formula \[4.85\text{ }g/cc\] is \[\begin{matrix}    A(g)  \\    2  \\    \underset{=x}{\mathop{(2-3x)}}\,  \\ \end{matrix}+\begin{matrix}    B(g)  \\    2  \\    \underset{=x}{\mathop{(2-3x)}}\,  \\ \end{matrix}\begin{matrix}    C(g)  \\    0  \\    3x  \\ \end{matrix}+\begin{matrix}    D(g)  \\    0  \\    3x  \\ \end{matrix}\begin{matrix}   (initially)  \\   (at\,equilibrium)  \\ \end{matrix}\] the solubility of an another salt having formula \[\Rightarrow \] is twice the molar solubility of \[2-3x=x\], the solubility product o \[\therefore \] is

A) \[x=\frac{1}{2}\]       

B) \[{{K}_{P}}=\frac{{{p}_{C}}.p{{  }_{D}}}{{{p}_{A}}.{{p}_{B}}}\]  

C) \[=\frac{{{\left( \frac{3x}{V} \right)}^{2}}}{{{\left( \frac{2-3x}{V} \right)}^{2}}}\]    

D) \[=\frac{9\times {{\left( \frac{1}{2} \right)}^{2}}}{4-12\times \frac{1}{2}+9\times {{\left( \frac{1}{2} \right)}^{2}}}\]