question_answer

If heavy water is taken as solvent instead of normal water while performing Cannizaro reaction, the products of the reaction are

A) \[{{[CrC{{l}_{6}}]}^{3-}}\]

B) \[C{{l}^{-}}\]

C) \[U{{F}_{6}}=233+19\times 6=347\]

D) \[\frac{dN}{dt}=kN\]

Correct Answer: B

Solution :

If \[{{n}_{1}}=1\] (heavy water) is taken instead of \[{{n}_{2}}=2\], as solvent, the reaction takes place in the following manner: