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AIIMS AIIMS Solved Paper-2009

  • question_answer
    The minimum voltage required to electrolyse alumina in the Hall-Heroult process is (Given, \[\Delta G_{f}^{o}(A{{l}_{2}}{{O}_{3}})=-1520\,kJ\,mo{{l}^{-1}};\]                                 \[\Delta G_{f}^{o}(C{{O}_{2}})=-394kJmo{{l}^{-1}}\]

    A) \[1.575V\]                          

    B) \[1.60V\]            

    C) \[1.312V\]          

    D)        \[-2.62V\]

    Correct Answer: B

    Solution :

    In Hall-Heroult process, the following reactions occur \[{{n}_{r}}=3\] \[{{n}_{p}}=2\] \[{{n}_{p}}\]   \[{{n}_{r}}\] \[N{{O}_{2}}\] \[\pi \] \[\pi \] \[\pi \]


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