A) top of the circle
B) bottom of the circle
C) half way down
D) None of the above
Correct Answer: A
Solution :
The force on string \[5\sqrt{3}\times {{10}^{-7}}N-m\] \[5\sqrt{3}\times {{10}^{-10}}N-m\] Centripetal force = \[\frac{\sqrt{3}}{5}\times {{10}^{-7}}N-m\] Tension at the top of circle \[\Omega \] \[=10+16=26N\]You need to login to perform this action.
You will be redirected in
3 sec