A) mgh
B) \[l\] mgh
C) \[2l\] mgh
D) \[\frac{l}{2}\] mgh
Correct Answer: C
Solution :
Increase in gravitational potential energy \[\frac{8}{3}V\] \[l\] \[5\sqrt{3}\times {{10}^{-7}}N-m\] \[5\sqrt{3}\times {{10}^{-10}}N-m\] \[\frac{\sqrt{3}}{5}\times {{10}^{-7}}N-m\] [\[\Omega \]\[1\mu F\]]You need to login to perform this action.
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