A) \[{{C}_{4}}\]
B) \[\frac{22}{3}\]
C) \[\frac{3}{22}\]
D) \[\frac{7}{4}\]
Correct Answer: C
Solution :
We know that \[=[M{{L}^{2}}{{T}^{-2}}{{\theta }^{-1}}]\] \[\Delta x=4mm=4\times {{10}^{-3}}m\] or \[\Delta T={{32}^{o}}C\] \[\frac{\Delta Q}{\Delta T}=200kcal/h\] \[=\frac{200\times 1000\times 4.2}{60\times 60}J/s\]You need to login to perform this action.
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