A) 1.0 A
B) 50 A
C) 0.5 A
D) 5.0 A
Correct Answer: C
Solution :
The emf of coil \[n=\frac{1}{2\pi }\sqrt{\frac{g}{l}}\] and current \[[M{{L}^{2}}{{T}^{-2}}{{\theta }^{-1}}]\] So, the current in the coil \[[{{M}^{2}}L{{T}^{-2}}\theta ]\] \[[M{{L}^{3}}{{T}^{-2}}{{\theta }^{-1}}]\] \[4\sqrt{\frac{h}{g}}\] \[2\sqrt{\frac{h}{g}}\]
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