AIIMS AIIMS Solved Paper-2010

  • question_answer
    If the value of g at the surface of the earth is \[9.8\,\,/m/{{s}^{2}}\] then the value of g at a place 480 km above the surface of the earth will be (.radius of the earth is 6400 km)

    A)  \[8.4\,m/{{s}^{2}}\]                                      

    B)  \[9.8\,m/{{s}^{2}}\]          

    C)           \[7.2\,m/{{s}^{2}}\]      

    D)        \[4.2\,m/{{s}^{2}}\]

    Correct Answer: A

    Solution :

    The value of g on the surface of the earth \[g\propto \frac{1}{{{R}^{2}}}\] At height h from the surface of the earth \[R=\frac{pV}{T}=\frac{[M{{L}^{-1}}{{T}^{-2}}][{{L}^{3}}]}{[\theta ]}\] \[=[M{{L}^{2}}{{T}^{-2}}{{\theta }^{-1}}]\]  \[\Delta x=4mm=4\times {{10}^{-3}}m\] \[\Delta T={{32}^{o}}C\]


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