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AIIMS AIIMS Solved Paper-2010

  • question_answer
    0.037 g of an alcohol, \[R-OH\] was added to \[{{C}_{2}}{{H}_{5}}MgI\] and the gas evolved measured \[11.2\text{ }cc\] at STP. The molecular mass of \[R-OH\]will be

    A) 47                          

    B)        79                          

    C) 77                          

    D)        74

    Correct Answer: D

    Solution :

    \[\underset{?}{\mathop{\underset{0.037}{\mathop{R-OH}}\,}}\,+{{C}_{2}}{{H}_{5}}MgI\xrightarrow{{}}\underset{\underset{22400cc}{\mathop{11.2cc}}\,}{\mathop{{{C}_{2}}{{H}_{6}}}}\,+RMgI\] \[\because \]11.2 cc gas is evolved by alcohol = 0.037 g \[\therefore \] 22400 cc gas will be evolved by alcohol \[=\frac{0.037}{11.2}\times 22400\] \[=74g\]


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