A) \[1.2\times {{10}^{2}}\text{ }eV\]
B) \[2.15\times {{10}^{3}}eV\]
C) \[7.6\times {{10}^{3}}eV\]
D) \[8.12\times {{10}^{3}}eV\]
Correct Answer: C
Solution :
Energy of photon, \[E=\frac{hc}{\lambda }=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.5\times {{10}^{-10}}}\] \[=1.32\times {{10}^{-15}}J\] Energy of ejected electron, \[E=\frac{1}{2}m{{v}^{2}}\] \[=\frac{1}{2}\times 9.1\times {{10}^{-31}}\times {{(1.5\times {{10}^{7}})}^{2}}\] \[=1.024\,\times {{10}^{-16}}\] Total energy of photon = binding energy of electron + energy of ejected electron \[1.32\times {{10}^{-15}}=\]binding energy \[+1.024\times {{10}^{-16}}\] \[\therefore \] Binding energy \[=(1.32\times {{10}^{-15}})-(1.024\times {{10}^{-16}})\] \[=1.2176\times {{10}^{-15}}J\] \[=\frac{1.2176\times {{10}^{-15}}}{1.6\times {{10}^{-19}}}eV\] \[=7.6\times {{10}^{3}}eV\]
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