A) \[P=\left( \frac{RT}{2V-b}-\frac{a}{4{{b}^{2}}} \right)\]
B) \[\mu =\frac{1}{2}\]
C) \[\mu =\frac{m}{M}\]
D) \[\Rightarrow \]
Correct Answer: B
Solution :
Gravity, \[P=\left( \frac{RT}{2V-b}-\frac{a}{4{{b}^{2}}} \right)\] (G is constant) \[\mu =\frac{1}{2}\] \[\mu =\frac{m}{M}\] \[\Rightarrow \] \[m=\mu M=\frac{1}{2}\times 44=22g\] Also, \[n=\frac{1}{2\pi }\sqrt{\frac{g}{l}}\]\[[M{{L}^{2}}{{T}^{-2}}{{\theta }^{-1}}]\] \[[{{M}^{2}}L{{T}^{-2}}\theta ]\] \[[M{{L}^{3}}{{T}^{-2}}{{\theta }^{-1}}]\] \[4\sqrt{\frac{h}{g}}\] \[2\sqrt{\frac{h}{g}}\]
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