A) \[{{k}_{1}}\] will increase faster than\[{{k}_{2}}\] , but always will remain less than \[{{k}_{2}}\]
B) \[{{k}_{2}}\] will increase faster than \[{{k}_{1}}\]
C) \[{{k}_{1}}\] will increase faster than \[{{k}_{2}}\] and becomes equal to \[{{k}_{2}}\]
D) \[{{k}_{1}}\]will increase faster than \[{{k}_{2}}\] and becomes greater than \[{{k}_{2}}\]
Correct Answer: A
Solution :
\[\frac{d(In\,k)}{dt}=\frac{{{E}_{a}}}{R{{T}^{2}}}\] As \[{{E}_{a}}\] increases, rate of increase in k also increases so \[{{k}_{1}}\] will increase faster than \[{{k}_{2}}\] but always will remain less than \[{{k}_{2}}\].You need to login to perform this action.
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